Viet The Vu
The fact that the limit goes to 0 when x != 0 stems from the fact that when x approaches infinity, e^(-x^2) goes to 0 much faster than 1/x
@Viet sounds reasonable to me
PS: You can replace 1/(sqrt(t)) with x and let x go to infinity
Does there exist a certain threshold of noise when random walk overpowers the deterministic evolution?
Or is this effect continuously dependent on the magnitude of noise?